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Write (3 + 2√5)/(7 + 3√5) in the form a + b√5

First multiply top and bottom by conjugate of denominator, (7-3√5), and expand(3 + 2√5)(7 - 3√5)/(7 + 3√5)(7 - 3√5)(21 + 14√5 - 9√5 - 30)/(49 + 3√5 - 3√5 - 45)Simplify top and botton(-9 + 5√5)/4Write in r...

BA
Answered by Beth A. Maths tutor
5642 Views

Expand using binomial expansion (1+6x)^3

(1+6x)^3 = 1+3(6x) +(3)(2)(36x^2)/2 + (3)(2)(1)(216x^3)/6
= 1+18x+108x^2 + 216x^3

OO
Answered by Ola O. Maths tutor
4057 Views

Determine the next two terms in this sequence: 2, 7, 9, 16, 25, ... , ...

In this sequence, there is no common difference between one term and the next making it more challenging to solve. However, if you look at the terms closely, you can see that each term is the sum of the p...

EW
Answered by Eleanor W. Maths tutor
12041 Views

Find the gradient at the point (0, ln 2) on the curve with equation e^2y = 5 − e^−x

Question is asking for gradient at x = 0, y = ln2. e^2y = 5 - e^-x. Differentiation with respect to x: 2e^2y * dy/dx = e^-x . dy/dx = e^-x / 2e^2y. At x = 0, y = ln2 ~ dy/dx = e^0 / 2e^2ln2 = 1 / 2e^ln4 =...

LK
Answered by Lokmane K. Maths tutor
5169 Views

1. (a) Find the sum of all the integers between 1 and 1000 which are divisible by 7. (b) Hence, or otherwise, evaluate the sum of (7r+2) from r=1 to r=142

1a) 1000/7=142.8.... Therefore there are 142 multiples of 7 between 1 and 1000
Therefore the sum of series from 1 to 142 is 1/7th of the solution
Calculation:70.5142143=71071
...

JF
Answered by Jack F. Maths tutor
5718 Views

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