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A curve has parametric equations x= 2sin(t) , y= cos(2t) + 2sin(t) for -1/2 π≤t≤ 1/2π , show that dy/dx = - 2sin(t)+ 1

A parametric equation is where both x and y are expressed separately, in terms of a parameter (t). In order to differentiate them we must use the chain rule, which here would be dy/dx= dy/dt ÷ dx/dt. The ...

Answered by Katie L. Maths tutor
12868 Views

Work out the angle between the two tangents of the curve y = sin(x) at y = 0 and y = 1

First we take the derivative of the function, this gives us dy/dx = cos(x)
Now we work out the different x values for y = 0 and y = 1.
sin(x) = 0 => x = 0, sin(x) = 1 => x = pi/2 (90 degre...

Answered by Kieran J. Maths tutor
1065 Views

The perimeter of an isosceles triangle is 16cm. The length of the base of the triangle is x+4 and that of the other two sides is x+3. Find the area of the triangle

16=2(x+3)+(x+4)16=2x+6+x+46=3xx=2 - Therefore the base has length 6
a=6y/2 - where y is the perpendicular heighty^2=5^2-3^2y^2=25-9y^2=16y=4
Therefore a=(6*4)/2 a=12 cm^2

Answered by Philip F. Maths tutor
3640 Views

Find the coordinates and the point of intersection between the lines 8x + 7y = 11 and y = 5x + 2

Substitute y = 5x + 2 into 8x + 7y = 11 to get, 8x + 7(5x + 2) = 11This simplifies down to 8x + 35x + 14 = 11And further simplifies to 43x = -3 giving the solution x = -3/43Substituting the x solution bac...

Answered by Adam R. Maths tutor
2387 Views

Integrate lnx with respect to x

= xlnx - the integral 1/x X x with respect to x= xlnx - the integral of 1 with respect to x= xlnx - x + c

Answered by Sam B. Maths tutor
1019 Views

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