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A rectangle has the side lengths root6m and root3m, what is the area of the rectangle in its simplest form.

This question explores surds. To find the area of a rectangle we must multiply its two sides together. When multiplying surds we follow the rule that roota x roota = rootaxa, therefore in this case by mul...

Answered by Hanah K. Maths tutor
3842 Views

(9-x)/2 = 2x - 8

(9-x)/2 = 2x - 8 Firstly, we want to multiply both sides by two to get rid of the fraction:9-x = 2(2x - 8)Open up the brackets:9 - x = 4x - 16Finally, we want to get the x's on one side and the numbers on...

Answered by India G. Maths tutor
1966 Views

Completing the Square

A curve has an equation y = 2x2 – 5x + 12a.      Write y = 2x2 – 5x + 12 in the form a(x + m)2 ...

Answered by Andre d. Maths tutor
2278 Views

Solve the simultaneous equations. 5x + y = 21 and x-3y = 9

Label the equations, [a] 5x + y =21 and [b] x-3y =9. [b]: x - 3y = 9, [c]: x = 3y + 9. Substitute [c] into [a] 5(3y + 9) + y = 21 , 16y + 45 = 21 16y = -24 , y = - 3/2. Substitute y = -3/2 into [b]: x + 9...

Answered by Solomon K. Maths tutor
2179 Views

The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.

The first step should be to rearrange the equation of the perpendicular line to PQ, in order to find the gradient, which works out to -3/2x. This can be done using the equation y=mx+c, where m is the grad...

Answered by M D. Maths tutor
5777 Views

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