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y = arcsec(x), Find dy/dx.

The key to this problem is to apply sec to both sides, and then differentiate implicitly: sec(y)=x; dsec(y)/dx = 1; tan(y)sec(y)dy/dx = 1; dy/dx = 1/(tan(y)sec(y)). Then using the fact that sec(y)=x and t...

Answered by Nicholas Y. Maths tutor
3861 Views

When solving a trigonometric equation, like sin(x) = -1/3 for 0 ≤ x < 2π, why do I get an answer outside the range? Why are there many correct answers for the value of x?

Drawing the graphs of the trigonometric functions sin, cos & tan, we can see that they all extend along the x-axis to infinity. Indeed, the sin & cos functions move between 1 and -1 on the y-axis,...

Answered by Alexandra G. Maths tutor
7878 Views

How do you solve a simultaneous equation by 'substitution'?

Firstly, demonstrate with an example: Solve: 3x + y = -9 and x2 + 2x - 3 = yRearrange the first equation to get "y" by itself by moving parts of the equation to the other side e.g. y ...

Answered by Sophie H. Maths tutor
2503 Views

What is the length of the hypotenuse of this right angled triangle?

Pythagoras theorem can be used to calculate the length x of the triangle. The length of the hypotenuse is equal to the square root of a2 + b2. When given length a and b, you are able...

Answered by Callum A. Maths tutor
2668 Views

how do you find intersections between two graphical functions?

When two lines intersect, the point of intersection will be a finite set of coordinates which can be obtained from the equation of either line. A sketch of the the functions will help you identify how man...

Answered by William J. Maths tutor
2230 Views

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