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Show that (sec(x))^2 /(sec(x)+1)(sec(x)-1) can be written as (cosec(x))^2.

( sec2(x))/((sec(x)+1)(sec(x)-1))Then, by the rule of 'difference of two squares', we know that this equals= (sec2(x))/(sec2(x)-1)= (sec2x/tan2x)s...

Answered by Rishi S. Maths tutor
10204 Views

Work out ∛16 as a power of two. (AQA GCSE Higher paper 2017, Q24b)

When you're working with fractional indices, I find the following rhyme really useful:"Fractional indices are like a flower: the bottom's the root, the top's the power".We have a cube root <...

Answered by Ruth D. Maths tutor
18457 Views

Two apples and three bananas cost a total of £1.30. Seven apples and one banana cost a total of £1.70. Find the cost of a) one apple and b) one banana.

First, look at the key information from the question and form an equation for each of the first two sentences. These equations are as follows (let a represent the number of apples and b represent the numb...

Answered by James S. Maths tutor
14656 Views

Find the values of A between and including 0 and 360 degrees for tan(2A) = 3tan(A)

You cannot work with this equation in the current form so you must use identities to find an equivalent form that you can work with. It is known that tan(2A) = 2tan(A) / 1-tan2(A) so set this e...

Answered by Daniel M. Maths tutor
3932 Views

Express the equation cosecθ(3 cos 2θ+7)+11=0 in the form asin^2(θ) + bsin(θ) + c = 0, where a, b and c are constants.

We must first use the identity cosecθ = 1/sinθ. Now the equation becomes (1/sinθ)(3 cos 2θ+7)+11=0. Since we know that the question is asking for the answer in the form of asin2θ + bsinθ + c = ...

Answered by George L. Maths tutor
5665 Views

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