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Solve the simultaneous equations to find x and y: 3y - x = 12 y + 2x = -3

3y - x = 12 (1)y + 2x = -3 (2)multiply equation (2) by 3: 3y + 6x = -9 (3)subtract equation (1) from equation (3): 3y + 6x - 3y + x = -9 -12 7x = -21 x = -3substitute x into equation (2): y -6 = -3 y = 3a...

Answered by Chloe G. Maths tutor
3439 Views

Differentiate y = x^3− 5x^2 + 3x

the rule for differentiating in terms of x is to multiply by the power then decrease the power by one. So going through the equation x^3 will be multiplied by 3 and go to x^2 so will be 3x^2. Then its imp...

Answered by Georgia D. Maths tutor
6718 Views

I have £300 I want to split between my daughters Megan, Danni and laura in the ratio 3:4:1 respectively. How much money will Danni get?

Firstly, we need to add up how many 'parts' this money is being split into by adding the ratio, 3+4+1 = 8 parts. Now we need to calculate how much one part is equal to by splitting our £300 into the 8 par...

Answered by Holly M. Maths tutor
2613 Views

Expand the following quadratic expression: (2x+4)(x-5)

Multiply the first terms in both brackets:2xx= 2x2
Next multiply the first term of the first bracket and the second term of the second bracket:2x
-5= -10x
Multiply...

Answered by Meera P. Maths tutor
4960 Views

Jack has 20 sweets. Will also has 20 sweets. Jack gives Will x sweets. Jack then eats 5 of his sweets. Will then eats half of his sweets. Write expressions for the number of sweets Jack and Will now have.

They both start with 20 sweets. To get the total number of sweets that Jack has, you need to take away x because that is the amount that he gives to will. Jack then eats 5 of his sweets so you need to tak...

Answered by Lucy M. Maths tutor
4436 Views

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