Top answers

Physics
All levels

A cyclist rides 10km. In the first 5km, they climb a hill, averaging 10km/h. In the second 5km, they descend the hill, averaging 30km/h. What is their average speed over the full 10km?

A common response from the student for the above question is: “I got 20km/h but it says it’s wrong! help i’m really confused”. The following two paragraphs will outline how I might attempt explain this id...

SB
Answered by Shihabul B. Physics tutor
3492 Views

A hot air balloon is travelling at a speed of 5.0m/s at an angle of 60.0 degrees up from the horizontal. Find the vertical and horizontal components.

The diagram would have the following:

An arrow pointing upwards labeled v(y)

An arrow pointing to the right labeled v(x)

An arrow pointing in between those lines with a degree between...

MB
Answered by Marta B. Physics tutor
2282 Views

Define the resistivity of a metal wire

ρ = (AR) / l

where:

ρ is the resistivity of the metal wire

A is the cross sectional area of the specimen wire

R is the electrical resistance of  a uniform metal wire

l i...

JE
Answered by Javier E. Physics tutor
3452 Views

A 15kg cannonball and a 1kg football are dropped to the ground from a height of 10 metres. Calculate the speed of the cannonball and of the football just before they hit the ground (you may ignore air resistance).

Aim of question: demonstrate that the speed of a dropped object is independent of its mass, and depends only on the height it is dropped from.

Solution: equate formulae for kinetic energy and for g...

WR
Answered by Will R. Physics tutor
2355 Views

Calculate the momentum of a 5 tonne truck at 50km/h

We know momentum= mass (kg) X Velocity (m/s)

So we need to do these conversions:  1tonne=1000kg so 5 tonnes is 5x1000kg = 5000kg 

There are 1000km in a meter so 50x1000= 50000m/h to get this...

CZ
Answered by Callum Z. Physics tutor
2641 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning