Top answers

All subjects
All levels

Show that the equation 2sin^2(x) + 3sin(x) = 2cos(2x) + 3 can be written as 6sin^2(x)+3sin(x) - 5 = 0. Hence solve for 0 < x < 360 degrees. Giving your answers to 1.d.p.

2sin^2(x) + 3sin(x) = 2cos(2x) + 32sin^2(x) + 3sin(x) = 2(cos^2(x) - sin^2(x) ) + 32sin^2(x) + 3sin(x) = 2(1- 2sin^2(x) ) + 32sin^2(x) + 3sin(x) = 2 - 4sin^2(x) + 36sin^2(x) + 3sin(x) - 5 = 0 let sin(x) =...

TA
Answered by Tom A. Maths tutor
3372 Views

‘The Bennet family are an embarrassment to Elizabeth.’ How far do you agree with this view? (Taken from OCR 2017 paper)

In guiding my pupil's response to this question, I would first draw attention to the phrasing of the question - 'How far do you agree' as indicative of a well-rounded and considered response - th...

EF
Answered by Esme F. English tutor
2046 Views

Quel rôle la propagande a-t-elle joue dans le régime Vichy ?

Au sommet du Régime Vichy, des centaines de milliers d'affiches et de bustes ont été produits, le profil de Pétain était sur les timbres-poste, et des chansons ont été écrites au sujet de Pétain pour proc...

KW
Answered by Katherine W. French tutor
1461 Views

The curve C has equation y = (x^2 -4x - 2)^2. Point P lies on C and has coordinates (3,N). Find: a) the value of N. b) the equation of the tangent to C at the point P, in the form y=mx+c where m and c are constants to be found. c) determine d^2y/dx^2.

a) Sub x=3 into the given equation. N is found to be 25.b) Finding dy/dx gives me, as the first differential is the gradient.First differentiate the power and then multiply the differential of the express...

TA
Answered by Tom A. Maths tutor
3814 Views

Why does the left side of the heart contain more muscle?

The left side of the heart contains oxygenated blood delivered by the pulmonary vein from the lungs. This blood must be pumped to the rest of the body, therefore more muscle is required to generate enough...

FM
2429 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences