Solve the following quadratic equation x^(2)+7x+12
(x+a)(x+b) = 0The two numbers must have a product of 12 and a sum of 7.3*4 = 12 AND 3+4=7Therefore(x+3)(x+4) = 0Therefore x+3 = 0 --> x = -3OR x+4 = 0 --> x = -4
MV
(x+a)(x+b) = 0The two numbers must have a product of 12 and a sum of 7.3*4 = 12 AND 3+4=7Therefore(x+3)(x+4) = 0Therefore x+3 = 0 --> x = -3OR x+4 = 0 --> x = -4
