Express 280 as a product of its prime factors.

2 * 2 * 2 * 5 * 7 = 280

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how would you solve the simultaneous equations 3x + 4y = 11, 5x - y = 3?


Jo wants to work out the solutions of x^2 + 3x – 5 = 0 She says, ‘‘The solutions cannot be worked out because x^2 + 3x – 5 does not factorise to (x + a)(x + b) where a and b are integers.’’ Is Jo correct?


a) If x=4, work out 3(x^2). b) Solve 6x-3=x+11


Expand (2x+1)(x+4)


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