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-Tangent is a straight line that touches, but does not intersect, the curve at the point (2,8).
We need to find the gradient of the curve at the point (2, 8). To do this, expand the equation, diffe...
To solve this we must use the chain rule which is dy/dt * dt/dx. Firstly, we differentiate dy/dt. For this we must use the quotient rule, this gives us dy/dt=(9te^3t - 3e^3t)/9t^2. Now for dx/dt, by subst...
You can not integrate tan2x but you can integrate sec2x Since sec2x = 1 + tan2x Then tan2Answered by Nandini P. • Maths tutor19885 Views
To start with, try and spot whether or not two of the coeffecients (numbers next to the letters) are the same for either question (i.e. could be a 3x in one equation and a 3x in the other). This also work...
Unit circle: x2 + y2 = 1 when x = sqrt(3)/2: y2 = 1 - (sqrt(3)/2)2 y2 = 1 - 3/4 y2 = 1/4 y = 1/2 or -1/2 (first quadrant, so y is posi...
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