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For a curve of gradient dy/dx = (2/(x^2))-x/4, determine a) d^2y/dx^2 b) the stationary point where y=5/2 c) whether this is a maximum or minmum point and d) the equation of the curve

a) Differentiating gives d²y/dx²=-4x^-3-1/4

b) Let dy/dx=0 and rearrange to find x=2

c) Inserting x=2 into d²y/dx²=-4x^-3-1/4 ...

Answered by Katie M. • Maths tutor

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Find ∫ ( 2x^4 - 4x^(-0.5) + 3 ) dx

When integrating, you need to add one to the power and divide the term by the power. We will consider each term individually, 2x⁴ will become (2x⁴⁺¹)/(4+1) = (2x⁵)/5, -4x<...

Answered by Rebecca M. • Maths tutor

6627 Views

A curve has equation y = f(x) and passes through the point (4,22). Given that f'(x) = 3x^2 - 3x^(1/2) - 7 use intergration to find f(x).

As f '(x) is the differential of f(x) we have to first integrate f '(x). To do this we take each term individually and integrate it. So starting with 3x², to integrate a simple function of x li...

Answered by Jonathan O. • Maths tutor

7047 Views

how do you do binomial expansion when the power is a negative

There is a simple equation, similar to the normal binomial expansion, thats easy to remember once youve used it a few times.

(1+x)ⁿ=1+nx+{[n(n-1)]/2!}x²+{[n(n-1)(n-2)]/3!}x

Answered by Sarah M. • Maths tutor

8339 Views

Why does differentiation give us the results that it does?

A quick analysis here is based on the fact that y=(x²). A big change is worked out between two points. The gradient between x=1 and x=2 is equal to 3. BUT we know the gradient is constantly cha...

Answered by Alexander A. • Maths tutor

3379 Views