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This is about a topic called graph transformations. It can get quite complicated, but the lucky thing here is that each question can be broken down into steps.
So considering the first question wit...
We want a solution to ax^2+bx+c=0. Complete the square to get a[(x+b/2a)^2 -(b^2)/(4a^2)]+c=0. Expalding brackets and rearanging gets a(x+b/2a)^2=(b^2)/4a -c. Divide by a to get (x+b/2a)^2= b^2/4a^2 -c/a=...
Solution:
V = V(0) + a*t
From the question: a = (-3i + 12j); Answered by Artur R. • Maths tutor6027 Views
The differential of a function is defined by the expression: dy/dx = Lim(dx->0) of (f(x+dx)-f(x))/dx. For functions only involving powers of x, the differentioal can easily be calculated by timesing by...
Let eqn. 1 be: 3x + 2y - 1 = 0 & Let eqn. 2 be: 4x - 6y -10 = 0
Multiply eqn. 1 by a factor of 3, and add the two eqautions together. (This eliminates y from the equation)
This gives: 9...
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