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Maths
A Level

For the curve, y = e^(3x) - 6e^(2x) + 32 ,find the exact x-coordinate of the minimum point and verify that the y-coordinate of the minimum point is 0.

At the minimum point, the gradient will be zero, so we differentiate the equation, giving us dy/dx = 3e3x - 12e2x. If the gradient is zero at the minimum point, we can set dy/dx = 0,...

Answered by Matthew A. Maths tutor
6425 Views

(https://qualifications.pearson.com/content/dam/pdf/A-Level/Mathematics/2013/Exam-materials/6666_01_que_20160624.pdf) Question 6.(i)

First split up the fraction into partial fractions as this is more easily integrated. It can be seen that the denominator has factors y and (3y+2), therefore we can say the original fraction is equal to p...

Answered by Tom J. Maths tutor
3166 Views

How to integrate 5x^2?

Firstly we integrate x^2 with respect to x which is (x^3)/3 as we integrate polynomials by adding a power then dividing by that power, (x^n+1)/n+1.Then we multiply by the 5 we have from earlier which give...

Answered by Matthew L. Maths tutor
18065 Views

Integrate f(x): f(x) = (3x +2) / (x^2 - 5x +6)

Split into partial fractions: (3x +2) / (x2 - 5x +6) = A / (x-3) + B / (x-2) => 3x + 2 = A(x-2) + B(x-3) let x =...

Answered by Oliver H. Maths tutor
5036 Views

Find dy/dx of y=e^xcosx

Use product rule i.e. (uv)'=u'v+uv'Set u=e^x and differentiate to find u'=e^x Set v=cosx and differentiate to find v'=-sinxTherefore (uv)' where uv=e^xcosx =e^xcosx + e^x(-sinx)=e^xcosx - e^xsinx=e^x(cosx...

Answered by Henry B. Maths tutor
4718 Views

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