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f(x) = x3 + 2x2 - x - 2 Use the factor theorem to test for f(1) = 0 f(1) = 13 + 2*12 - 1 - 2 = 0 Therefore x = 1 is a solution and (x-1) is a factor of f(x) Now...
Differentiation dy/dx = 2+12x^2+12x^3Chain ruleu = 1+xz=u^2dz/dx = dz/du * du/dx = 2u * 1 = 2(1+x)
Start by expanding (a+b)7, using Pascal's Triangle or the binomial coefficient function to work out the coefficients:a7 + 7a6b + 21a5b2 + 35a4Answered by Josef W. • Maths tutor6650 Views
First substitute: u = 1 - 3xNext calculate: du/dx = -3 .... therefore dx = (-1/3) * duNow re-arrange the expression: Integrate 1/u * ( -1/3)*duNext recall the integral of 1/x is the natural logarithm, and...
f(x) = 8x3 + 1 / x3 >>> f(x) = 8x3 + x-3 f'(x) = 3(8x2 ) + -3(x-4) >>> f'(x) = 24...
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