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Maths
A Level

Prove that 2Sec(x)Cot(x) is identical to 2Cosec(x)

2 Secx = 2/CosxCotx = 1/Tan x = Cosx/SinxTherefore: 2SecCotx = 2/Cosx * Cosx/Sinx = 2/Sinx = 2Cosecx

Answered by Ben S. Maths tutor
3561 Views

If y^3 = 8.08, approximate y.

Firstly, recognize that 2^3 is 8, so y must be close to 8.It will be helpful to then write y^3 as y^3= 8 + 0.08We can then factorize out 8.y^3=8(1+0.01)If we try and take the cube root of this expression....

Answered by Sanjith H. Maths tutor
2278 Views

Differentiate the equation x^2 + 2y^2 = 4x

2X + 4Y (dy/dx) = 4 4Y (dy/dx) = 4 - 2X dy/dx = (4 - 2X) / 4Y

Answered by Adam K. Maths tutor
3584 Views

Simplify: (log(40) - log(20)) + log(3)

First, know the log rule: log(x) - log(y) = log(x/y)Second, know the log rule: log(a) + log(b) = log(ab)So, starting with the brackets: log(40) -log(20) = log(40/20) which is log(2).Now we have: log(2...

Answered by Edward R. Maths tutor
2968 Views

If (x+1) is a factor of 2x^3+21x^2+54x+35, fully factorise 2x^3+21x^2+54x+35

In order to find the other factors, we need to do polynomial division. We can do this by method of long division. We start by finding what we must times the x in (x+1) by to get the largest term of the po...

Answered by Jennifer G. Maths tutor
2574 Views

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