Top answers

Maths
A Level

Solve 2sec^2(x) = 3 + tan(x) for 0 < x <pi/2

Make use of identity sech^2(x) = tan^2(x) + 1

=> 2{tan^2(x) + 1} = 3 + tan(x)

Multiply out brackets and rearrange

=> 2tan^2(x) - tan(x) - 1 = 0

Use quadratic formula w...

Answered by Robert M. Maths tutor
7502 Views

What are stationary points and how do I find them?

If you have a differentiable function, stationary points are, by definition, those points where the derivative of the function is 0. Considering that the derivative of a function represents the rate of in...

Answered by Stefania G. Maths tutor
7818 Views

Find ∫(8x^3 + 4) dx

∫(8x3 + 4) dx = (8x^4)/4 + 4x + c= 2x^4 + 4x + c

Answered by Aikaterini I. Maths tutor
9000 Views

solve the equation 2cos x=3tan x, for 0°<x<360°

We know that tan x =sin x/cos x,

so we can multiply the whole equation by cos x which gives us => 2cos^2 x =3 sin x

from the trig identity sin^2 (x)+ cos^2 (x)=1, we can sub in cos^2 (x)...

Answered by Elizabeth G. Maths tutor
18593 Views

Factorise x^3+3x^2-x-3

Test factors of -3 to find a root for the equation. For example, try 1, 1^3+3*1^2-1-3=0, so 1 is a root, and (x-1) is a factor. Now it's known that: (ax^2+bx+c)(x-1)=x^3+3x^2-x-3. By comparing coefficient...

Answered by Sian C. Maths tutor
6154 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences