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That is a good question. Let me try to help you figure this out by working through a few simple examples. We know that differentiation is like a reverse process of right? So let us differentiate a few fun...
1
y = 4x^3-5x^-2 dy/dx = 12x^2+10x^-3
3tan(k)-1=sec^2(k) () We want to get this in the form of a quadratic equation in a single variable, and in this case the easiest variable is tan(k). To do this we use the trigonometric identity sec^2(...
Use the identity cos^2(x)+sin^2(x)=1, to change the 5sin^(x) into 5-5cos^2(x) and rearrange. Let y=sin(x) and solve the rearranged quadratic (6y^2-3y-3) for y and find the value of x for each solution. y=...
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