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Differentiate with respect to x: 3 sin^2 x + sec 2x

6 sinx cosx + (2 sin 2x)/(cos^2 2x)

Answered by Hugo M. • Maths tutor

10487 Views

How do you solve a quadratic inequality eg find the values of x for which x^2 -6x +2 < -3

First we must change our inequality so that we have a zero on one side, In this case we can add three to both sides of the inequality, this gives: x^2 - 6x +5 < 0 Now let's consider the equation y = x^...

Answered by Isobel R. • Maths tutor

3727 Views

2 equations intersect each other, y = x + 2 and y = x^2. Find the area of the shaded region between the points of intersection giving your answer to 3 significant figures. (shaded region will be shown)

points of intersection are (-1,1) and (2,4). Area of the shaded region is 4.5.

Answered by Syed A. • Maths tutor

2698 Views

What is the differential of y =sin(2x)?

For this question we have to use the chain rule. The chain rule is dy/dx (the differential you are looking for) = du/dx (the differential of u with respect to x) * dy/du(the differential of y with respect...

Answered by Cem U. • Maths tutor

5617 Views

Given that y=ln([2x-1/2x=1]^1/2) , show that dy/dx= (1/2x-1)-(1/2x+1)

y=ln([2x-1/2x=1]^1/2)- can be written as y= [0.5ln(2x-1)]-[0.5ln(2x+1)] due to laws of logs. Take first term -- (0.5ln(2x-1)) and substitute 2x-1 for u. so u=2x-1 and y=0.5lnu Now dy/du=1/2u and du/dx=2. ...

Answered by Sam F. • Maths tutor

10003 Views