First write cosh and sinh as exponentials, from their respective definitions:sinh x = 1/2 (ex - e-x)cosh x = 1/2 (ex + e-x)So: 3 * 1/2 (ex + e
In order to calculate the derivative of the given function, we need to apply the laws of derivation. Therefore:
f '(x) = ((x+2)/(x-1))'
f '(x) = [(x+2)' * (x-1) - (x+2) * (x-1)' ]/ (x-1)2