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Although an object in circular motion travelling at constant velocity isn't accelerating in the conventional sense, ie. changing speed, it's important to remember that it is a vector. Vector quantities ha...
Equate gravitational force (GMm/r^2) to centripetal force (mv^2/r). Rearrange to get v^2=GM/r. Due to the approximated circular orbit v=2pir/T so v^2=4pi^2r^2/T^2. Therefore GM/r=4pi^2r^2/T^2. Rearrangin...
At first glance this question seems require solving in several steps, splitting horizontal and vertical components, taking a value for time from the motion under constant acceleration and then applying th...
a) A geostationary orbit is when the satellite remains vertically above the same point on the equator at all all times and consequently has an orbital period of 24 hours. b) Use the equation T^2=4(PI)^2(r...
In the instant when the DVD is dropped, it will have an acceleration of g, with no drag force acting on it as it is not moving. As the DVD accelerates downwards, the drag force acting on it increases and ...
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