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Further Mathematics
GCSE

write showing all working the following algebraic expression as a single fraction in its simplest form: 4-[(x+3)/ ((x^2 +5x +6)/(x-2))]

4-[(x+3)*((x-2)/(x^2 +5x +6))]

4-[(x+3)(x-2)/(x^2 +5x +6))]

factorise denominator 

4-[(x+3)(x-2)/(x+3)(x+2)]

cancel down (x+3)

4-[(x-2)/(x+2)]

expand 

4(x+...

Answered by Sarah T. Further Mathematics tutor
10146 Views

Given y=x^3-x^2+6x-1, use diffferentiation to find the gradient of the normal at (1,5).

dy/dx = 3x^2-2x+6

At (1,5), dy/dx = 7. 7 is the gradient of the tangent, therefore the gradient of the normal at (1,5) is -1/7.

Answered by Katelyn R. Further Mathematics tutor
1687 Views

How can a system of two linear equations be solved?

There are, mainly, three ways of doing it easily:
Substitution: It consists in modifying one of the equations in such a way that x is expressed in terms of y  (or y in terms of x) and then substitut...

Answered by Pablo A. Further Mathematics tutor
2183 Views

x^3 + 2x^2 - 9x - 18 = (x^2 - a^2)(x + b) where a,b are integers. Work out the three linear factors of x^3 + 2x^2 - 9x - 18. (Note: x^3 indicates x cubed and x^2 indicates x squared).

There are a few different ways to approach this problem. The most obvious is to attempt to factorise x+ 2x- 9x - 18. However it is very difficult to approach the problem like thi...

Answered by Chris B. Further Mathematics tutor
3410 Views

Factorise 6x^2 + 7x + 2

6x^2 + 7x + 2 can be written in the form ax^2 + bx + c. In order to factorise this I use the following method which can be used to factorise similar equations. Multiply 'a' and 'c' to get ac (here this is...

Answered by Hannah P. Further Mathematics tutor
9594 Views

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