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Maths
GCSE

Express 56 as a product of its prime factors

56 7 x 8 products of 56, 7 is a prime factor 2 x 4 2 is a prime factor 2 x 2 Therefore, 56 as a product of its prime factors is 7 x 2 x 2 x 2 OR 7 x 2^3

Answered by Isabella T. Maths tutor
21405 Views

expand and simplify (x+4)(x-2)^2

(x+4)(x-2)^2(x+4)(x-2)(x-2)(x+4)(x^2-2x-2x+4)(x+4)(x^2-4x+4)x(x^2-4x+4)+4(x^2-4x+4)(x^3-4x^2+4x)+(4x^2-16x+16)x^3-12x+16

Answered by Bethany W. Maths tutor
3303 Views

To make 12 cakes you need 100g of butter, 6 eggs, and 40g of sugar. How many cakes can you make with 450g of butter, 15 eggs, and 110g of sugar?

To work this out you can either work out the amount of an ingredient needed for one cake then divide the amount you have by this or you can work out how many times the amount needed for 12 cakes goes into...

Answered by Celeste S. Maths tutor
3391 Views

Where do the two lines intersect? (a) 3x+6y= 15 (b) y= 6x -4 (GCSE-Higher Tier)

Substitute y=6x-4 into the equation 3x+6y=15 to eliminate y.You will then have the equation 3x+6(6x-4)=15.The next step is to expand the brackets given 3x+36x -24=15.The next step is to collect like terms...

Answered by Tutor114867 D. Maths tutor
3333 Views

v = u + at, u = 1 a = -3 t = 1/2, Work out the value of v.

Sub the values you have been given into the formula provided.v = u +atv = 1 + (-3 x 1/2)Solve the equation you have created, be careful to stick to rules of BIDMAS (or BODMAS)and do the calculation in the...

Answered by Olivia R. Maths tutor
13852 Views

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