Search over 10,000 free study notes

1. We aim to factorise the numerator. This would give 6c(c^2 + 5).

2. We then factorise the denominator. This would give 3(c^2 + 5).

3. Since (c^2 + 5) is present in b...

2kx + 6ky + 4kz

=2k (x + 3y + 2z)

6a + b = 16    Equation 1
5a - 2b = 19    Equation 2

Scale up one equation so both equations have same coeffient of one variable ie 2 times Equ 1

12a + 2b = 32
5a - 2b = 19

By factorising the expression, (x-5)(x-4)=0. This means that either (x-5)=0 or (x-4)=0. By solving these equations we can work out the solutions to be x=4,5.

What do we know about hexagons? They have six angles and vertices. The fact that the hexagon is regular implies that all interior angles are the same. We can split the hexagon up into six triangles. These...