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Multiply the first equation by 2, and the second by 3:

6x+10y=14

6x-9y=33

Subtract the second from the first:

19y=-19

solve for y:

y=-1

plug in to first eq...

At the x-axis, y is always zero at any point. If you want to fnd out whether or not a graph reaches the x-axis, then substitute y=0 into the equation and find the value of x. If it solves, then we know it...

x² -4=0 becomes (x+2)(x-2)=0

Either one of the two brackets has the value of 0.

If the first bracket is zero, then x+2=0, therefore x=-2

If the second bracket is zero, then...

divide fraction by 2

3x+2 / x-1  + 3 = 4

multiply by x-1

3x + 2 + 3x - 3 = 4x - 4

6x -1 = 4x -4

2x = -3

x= -3/2

This problem is a graphical representation of finding the solutions to a pair of simultaneous equations.

In this example we will use the curves y=2x² , and y=x²+1. This is a v...