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Maths
GCSE

solve the simultaneous equation: 3x+y=7, 2x+4y=8

First, we need to remove one of the variables from one of the equations. In this case, we multiply the first equation by 4 to give 12x+4y=28.Then minus the 2nd equation from this to give 10x+0y=20.Now div...

Answered by Matthew T. Maths tutor
3861 Views

Solve x for (x)/(4x-1) = (6x+5)/(12x+31)

First, we must cross multiply to remove the fractions, to do this, we multiply each numerator by the opposite denominator: (x)(12x+31) = (6x+5)(4x-1). Then, we multiply out the brackets t...

Answered by Elsie I. Maths tutor
4403 Views

'There are two adults and two children in the Adams family. They buy an all-day travel ticket for each person. The price is £8 for each adult and £5 for each child. They also buy 4 ice-creams at £1.95 each. How much do they spend in total?'

So the Adams family consists of 2 adults and 2 children. We know that all-day ticket for an adult is £8. Therefore the price for 2 adults would be:£8 x2 = £16. We also know that an all-day ticket for a ch...

Answered by Mukilan B. Maths tutor
2306 Views

Simplify √48

√48 = √3 x √16 = √3 x 4 = 4√3

Answered by Joshua W. Maths tutor
3292 Views

Simplify 3/(x+1) + (3x-9)/2 = 1, to get a quadratic equation in the format ax^2 + bx + c = 0.

First, add the two fractions together. The common denominator is 2(x+1), or 2x+2. The first fraction becomes 6/(2x+2). The second fraction becomes (x+1)(3x-9)/(2x+2), or (3x2-6x -9)/(2x+2). Add...

Answered by Maths tutor
3746 Views

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