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Draw a diagramRearrange the given equation into the form y = mx + cy = -3/2x+7/2Gradients of perpendicular lines - m1*m2=-1, so gradient of PQ = 2/3PQ : y=mx+c -> 4=(2/3)*3+cc=2, therefore PQ: y=2/3x+2...
Speed = Distance/TimeSpeed = 9000/11.25Speed = 800 km/h
2 x -4 = -8 -8 x 1 = -8 (2x^2-8x)+(x-4) 2x(x-4) + 1(x-4) (2x+1)(x-4)
sinx = o/h sinx x h =o sin30 x 8 = 4cm The opposite is 4cm
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