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Maths
GCSE

The perimeter of a right-angled triangle is 60 cm. The lengths of its sides are in the ratio 3 : 4 : 5. Calculate the area of the triangle.

We are given ratios of side lengths and the total perimeter. The perimeter of the triangle is simply the sum of the side lengths. Imagine that the sides are made up of "units": 3 times a unit + ...

VN
Answered by Viktoria N. Maths tutor
3175 Views

How do I solve a sum of equations with unknowns in the denominator?

First, you need to make sure that each equation has a common denominator. You do this by multiplying the numerators of each equation with the denominators of the others. This allows you to form one algebr...

KH
Answered by Kai H. Maths tutor
2962 Views

Solve algebraically for a and b: 6a+b=16, 5a-2b=19

Multiply equation 1) by 2 : 12a+2b=32. There are alternate signs of b and so therefore add the equations together: 17a=51. Solve for a: a=3. Sub a into one of the equations to find b: 5*3-2b=19b=-2. The f...

SS
Answered by Sorcha S. Maths tutor
2828 Views

Expand and simplify (6x + 10)(3x - 2)

Expand by multiplying out the brackets (using crab claws or similar method): 18x^2 + 30x - 12x -20Simplify by combining like terms: 18x^2 + 18x -20

GC
Answered by Grace C. Maths tutor
3515 Views

The perimeter of a right-angled triangle is 81 cm. The lengths of its sides are in the ratio 2 : 3 : 4. Work out the area of the triangle.

Answer is 243cm2. 2+3+4 = 981/9 = 9Non-hypotenuse sides of triangle are therefore length (9x2=18) and (9x3=27)Area of triangle is (18x27)/2 = 243

CA
Answered by Casey A. Maths tutor
3610 Views

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