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Maths
GCSE

Solve the simultaneous equations for x and y: 2x - 3y + 4 = 0 , x - 2y + 1 = 0.

Simultaneous equations can be solved either by substitution or elimination. Solving this by elimination:2x - 3y + 4 = 0 (1)x - 2y + 1 = 0 (2)To eliminate x, we can multiply both sides of the second equati...

Answered by Benjamin R. Maths tutor
5023 Views

8 pens in a bag, 3 blue, 5 red. 2 taken out at random, without replacement. Probability they are the same colour?

Either both blue or both red. 'OR' rule - add probabilities.Blue - first blue and second blue - 'AND' rule - multiply probabilities. 3/8 x 2/7 (as not replaced) = 6/56 = 3/28 (multiply top and bottom)Red ...

Answered by Amy S. Maths tutor
2575 Views

Solve: a) 5t + 17 = 2. b) x^3 - 25 = 103 - x^3.

a) 5t + 17 = 2. We want to work out what t is. t = ?.To do this we need to get t on it's own, so first we move all the other numbers to equal t.We do this by subtr...

Answered by James A. Maths tutor
2506 Views

Factorise the Quadratic: 3x^2 + 2x - 1.

When we are asked to factorise a quadratic we essentially need to tidy it up by putting it into brackets.For a quadratic we look to work out the sum and the product, however this time it's a bit different...

Answered by James A. Maths tutor
3779 Views

Where do the lines 2y = 4x + 2 and - 3x + y = 4 intersect?

Rearrange the second equation in the form y = mx + c to get y = 3x + 4. Divide the first equation by 2 to get y = 2x + 1. When the lines intersect, they'll have the same x and y values, hence, set the equ...

Answered by Emma J. Maths tutor
2282 Views

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