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Question: Factorise the expressions: 1. X^2 - 9 2. 2X^2 - 14X + 24

The ways to complete the first one is to realise that it involves a difference of two squares. If you were to see (X^2) with a constant (number), you know they have no factor in common, meaning the two te...

Answered by Yahya M. • Maths tutor

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The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle

Perimeter= 72Ratios are 3:4:5In total, you can think of there being 3+4+5=12 "portions".This means that in the perimeter includes 12 portions. 72/12=6 so each portion is worth 6cm.
Now we c...

Answered by Natasha A. • Maths tutor

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Expand (2x+4)(x-3)

2x^2 - 2x - 12

Answered by Amy S. • Maths tutor

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n is an integer such that 3n + 2 < 14 and 6n/(n^2+5) > 1. Find all possible values of n.

First of all, solving the equation 3n + 2 < 14 to find n. 3n < 14 -2 = 3n < 12. n < 12/3 = n < 4Secondly solve the equation 6n/(n^2+5) > 1 to find n. Collect all terms on one side of the...

Answered by Kai P. • Maths tutor

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Solve the quadratic equation (x^2)-x-12=0 (easy), (x^2)-9=0 (special case), (x^2)+5x-13=0 (quadratic formula)

For each of the above the methodology is fairly similar, first try and do it just by looking at it then try the quadratic formula if that doesn't work. At GCSE level I don't think there's any need to worr...

Answered by Jack E. • Maths tutor

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