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Maths
GCSE

The perimeter of a right-angled triangle is 72 cm. The lengths of its sides are in the ratio 3 : 4 : 5 Work out the area of the triangle.

72 / (3+4+5) = 6base :36 = 18height :46 = 24area = (base * height) /2area = (18*24)/2=216 cm ^2

IH
Answered by Ibrahim H. Maths tutor
2489 Views

Solve x^2+6x+1=0 by completing the square

x2+6x+5=0 First of all half the x coefficient and write (x+6/2)2 the take away the (6/2)2 and add on the 5
(x+3)2-9+5=0
(x+3)2-4=0 ...

BS
Answered by Ben S. Maths tutor
7615 Views

Expand 4e(e + 2)

4e^2 + 8e

Answered by Maths tutor
16552 Views

Factorise and solve the quadratic : 3x^2 + 15x +18 = 0

First we look to see if there is a common factor in the equation. In this case there is a common factor of 3, therefore we can take 3 out as a factor. 3(x2 +5x +6) = 0
The inside of the br...

HW
Answered by Holly W. Maths tutor
3980 Views

The equation of line 1 is: 3y-5x+3=0. The equation of line 2 is : y= 5x/3+9. Check whether the 2 lines intercept.

Rearranging the first equation: 3y=5x-3Then dividing by 3 so that the equation of the line will become in the form of y=mx+c, where m is the gradient and c is the interception point with the y-axis (0,c)W...

PG
Answered by Panagiotis G. Maths tutor
2904 Views

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