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Recall that to solve a quadratic it needs to be in the form ax² + bx +c = 0, Subtract 2 from each side to get 2x²-x-6=0 therefore a=2 b=-1 and c=-6 Solve by considering factors c and...

First write down explicitly what the elements of A and B are.A={15,20,25}, B={15,17,19,21,23,25}.
Remember ∪ means OR. So A ∪ B is the set of items which are in either A OR B. This is {15,17,19,21,23...

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket...

1. Multiply every term by a denominator to eliminate it;5 + 3(x+2)/(x-3) = 2(x+2)5 + 3x+6/(x-3) = 2x+45(x-3) + 3x+6= (2x+4)(x-3)2) simplify5x-15+3x+6=2x²-12+4x-6x8x-9=2x²-12-2x2x<...

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = ...