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Maths
GCSE

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket...

CL
Answered by Clarence L. Maths tutor
3697 Views

How do you solve an equation like: 5/(x+2) + 3/(x-3) = 2?

  1. Multiply every term by a denominator to eliminate it;5 + 3(x+2)/(x-3) = 2(x+2)5 + 3x+6/(x-3) = 2x+45(x-3) + 3x+6= (2x+4)(x-3)2) simplify5x-15+3x+6=2x2-12+4x-6x8x-9=2x2-12-2x2x<...
TH
Answered by Tom H. Maths tutor
5459 Views

Solve the simultaneous equations: x + 2y = 13, 4x - 3y = 8.

Multiply both sides of the equation x + 2y = 13 by 4 to get 4x + 8y = 52. Subtract 4x - 3y = 8 from 4x + 8y = 52 to get 11y = 44. Divide both sides of 11y = 44 by 11 to get y = 4. Since we now know y = ...

KP
Answered by Kate P. Maths tutor
5163 Views

Solve the simultaneous equations y = x^2 +3x and y = x+8

Because both of the equations are equal to y, the first thing we do is make them equal to each other:x^2 + 3x= x + 8We then want to rearrange the equation so that everything is on the same side of the equ...

JW
Answered by Jessica W. Maths tutor
3811 Views

solve the simultaneous equations: 3x + 5y = 4 ; 7x - 3y = 8

first recognise that if you double the first equation the both equations will be equal to 8.so now we have 6x + 10y = 8 ; 7x - 3y = 8now we can set the equations equal to each other to get 6x + 10y = 7...

EW
Answered by Elizabeth W. Maths tutor
3812 Views

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