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Maths
GCSE

solve the simultaneous equations x^2 + y^2 = 5 and 3x+1=y

Substitute in y to the first equationx2 + (3x+1)2 = 510x2 + 6x - 4 = 55x2+3x-2=0(5x-2)(x+1)x=2/5 or -1Sub these values of x into the first equationy=11/5 and -2...

Answered by Isabel D. Maths tutor
2537 Views

How do I solve the equation 5y+18=3y+4?

First collect the like terms on one side.(-3y) 2y+18=4Then solve as a normal equation.(-18) 2y=-14(÷2) y=-7

Answered by Aiman K. Maths tutor
2518 Views

The area of square ABCD is 10 cm^2 . Show that x^2 + 6x = 1 (requires diagram which I will draw on the whiteboard).

The area of a square is the length of one side squared (multiplied by itself), so for a square with side length 3, the area will be 32 or 3 x 3, which = 9. For a square with side length x, the ...

Answered by Matilda L. Maths tutor
18738 Views

How do I solve simultaneous equations? Such as 2x + 4y = 8, 3x + 2y = 8.

There are two easy ways to solve simultaneous equations. Substitution and elimination. In order to work with substitution we must rearrange one equation to be equal to either x or y. In this case, 2x+4y=8...

Answered by Cameron T. Maths tutor
6462 Views

Solve the simultaneous equations x+y=3 and-x+5y=-15.

Equation 1: x+y=3Equation 2: -x+5y=-15Step 1: Check to see if any variables (x or y) can be eliminated. As there is x in equation 1 and -x in equation 2, x can be eliminated by adding the equations togeth...

Answered by Katherine O. Maths tutor
3317 Views

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