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We can factorise the quadratic equation by noting that two numbers which multiply to get 24 and that add to get -10 are: -6 and -4. Therefore, we get (X-6)(X-4)=0 and we can solve for X to get X = 6 or X ...

I don't know what gcse entails but I'm certain I could teach it

1.Here the first task in this is to be able to identify the form of this quadratic polynomiala^2 - b^2This format is called the difference between two squares When you ge...

We are told that the line passes through the origin O (0,0) and the point P (-3,9). First we need to find the gradient of the line m; this is given by m = (change in y)/(change in x), hence m = (9-0)/(-3-...

Firstly we should look at the question and notice that the two possible methods are substitution or elimination. We should then notice that since one equation is a quadratic and the other linear, then the...