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First we need to be clear how to construct a proof by induction. It has two main parts, the base case and the inductive step. Let P(n) denote that the statement ...
First of all, transform both z1 and z2 into modulus-argument form. To obtain that form, you are going to need a modulus (the length of the hypotenuse on the Argand diagram) and argum...
First we can write d2y/dx2 as (d/dx)(dy/dx). Now we need to find dy/dx. This can be further written as (dy/dt)(dt/dx). These derivatives can be obtained from the given parametric equ...
Unlike if we had just x in the numerature, here the chain rule will do us no good. Integration by parts in this case also is little help - we end up with expressions at least as difficult as we started w...
Max and Mins occur where the slope of a graph equals zero.
To find this, if we take the 1st derivative of a function and set the derivative equal to zero to solve for x.
The values we solv...
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