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The quadratic equation x^2 - 2kx + (k - 1) = 0 has roots α and β such that α^2 + β^2 = 4. Without solving the equation, find the possible values of the real number k.

We know in a quadratic x^2 +bx + c = 0, -b/a = α + β and c/a = αβ. 

Therefore, α + β = -(-2k) = 2k, and αβ = k - 1. (Both are divided by the coefficient in front of x which is 1 so can be ignored.<...

Answered by Ralph T. Maths tutor
15273 Views

Consider the arithmetic sequence 2, 5, 8, 11, ... a) Find U101 b) Find the value of n so that Un = 152

Firstly, as with any question, make sure to check your formula book in order to find any relevant equations. In this case, the one most relevant to us is Un = U1 + d(n-1).
From...

Answered by Kirsty W. Maths tutor
11124 Views

IB exam question: Let p(x)=2x^5+x^4–26x^3–13x^2+72x+36, x∈R. For the polynomial equation p (x) = 0 , state (i) the sum of the roots; (ii) the product of the roots.

p(x) = 2x+ x– 26x3 – 13x+ 72x + 36
i) obtain the sum by using vieta's fomula: for p(x) the sum is hence -b/a hence, sum = -1/2
ii) obtain the ...

Answered by Niccolo M. Maths tutor
7002 Views

What is the equation of the tangent drawn to the curve y = x^3 - 2x + 1 at x = 2?

The equation of a two-dimensional non-vertical line can easily be determined if its gradient 'm' and a point on the line (x0, y0) is known, using the formula m = (y - y0) / (x - x0). The gradient of the t...

Answered by Mario Z. Maths tutor
1662 Views

a) Let u=(2,3,-1) and w=(3,-1,p). Given that u is perpendicular to w, find the value of p. b)Let v=(1,q,5). Given that modulus v = sqrt(42), find the possible values of q.

a) is perpendicular to w, so =0. This means that 23 + 3(-1) + (-1)*p = 0, so 6-3-p=0, hence p=3. b) The magnitude of v ...

Answered by Cristiana R. Maths tutor
3798 Views

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