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Maths
KS3

Solve the following equation: b - 6 = 13

b - 6 = 13Add 6 to both sides of the equationb - 6 + 6 = 13 + 6Therefore:b = 19

Answered by Claire M. Maths tutor
2187 Views

Where does the graph x^2-3x-4 cross the x axis?

First, you need to factorise the quadratic:x2-3x-4=0(x-4)(x+1)=0Then, set each of the brackets to equal 0 and solve for x:x-4=0 --> x = 4x+1=0 --> x=-1

Answered by Sarah B. Maths tutor
1434 Views

Differentiate sin^2(x)

sin(2x)

Answered by James P. Maths tutor
4034 Views

3/8 is equivalent to ?/24. Find the missing number.

Firstly, we work out what the fraction has been multiplied by. Since the bottom of the fraction is 24, we want to see how many 8's fit into 24. The answer is 3, since 8 multiplied by 3 is 24.Since the bot...

Answered by isabella B. Maths tutor
16907 Views

How can I factorise x^2 - 7x + 12?

So firstly, you want to split the equation into the format of a^2 + bx + c, so you know what a, b and c equal. a = 1b = -7c = 12 Now, you need to try to split the equation into the format (x + ?)(x + ?). ...

Answered by Georgia D. Maths tutor
2538 Views

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