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Calculate the empirical and molecular formula of the molecule giving rise to the molecular ion peak at 148 m/z. The percentage composition by weight is 64.80 % carbon, 13.62 % hydrogen, and 21.58 % oxygen

Step 1, pick out the important information from the question: Carbon: Hydrogen: Oxygen % by weight: 64.8: 13.62: 21.58 Step 2, from the periodic table, find out the relative atomic masses of each element:...

Answered by Olivia H. • Chemistry tutor

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How will a catalyst affect the position of equilibrium?

A catalyst is something that speeds up the rate of reaction, without being consumed during the reaction. If a catalyst is used in a reaction, it will only speed up the forward and backward reaction, howev...

Answered by Zareen K. • Chemistry tutor

7268 Views

Describe the electrons in Benzene

delocalised pi electronslower e density than alkeneshalogen carrier is needed to generate more powerful electrophile so reaction can take place with benzene
draw benzene and resonance hybrids

Answered by Imogen T. • Chemistry tutor

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Calculate the empirical and molecular formula of unknown compound A which gave an m/z of 181 in the mass spectrum for the molecular ion peak. Elemental analysis by combustion shows the compound is C 53%, O 35.4%, H 3.9% and N 7.7%.

C atomic mass-12 C percentage by composition: 53% Atomic ratio of C: 53/12= 4.417 H atomic mass-1 H percentage by composition: 3.9% Atomic ratio of H:...

Answered by Aminat S. • Chemistry tutor

2815 Views