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Further Mathematics
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A circle has equation x^{2}-8x+y^{2}-6y=d. A line is tangent to this circle and passes through points A and B, (0,17) and (17,0) respectively. Find the radius of the circle.

Gradient of line: (0-17)/(17-0)= -1 equation of line: y-y1=m(x-x1) y-17=-1(x-0) y=17-x equation of circle: (x-4)2+(y-3)2-25=d (completing the square) (x-4)...

Answered by Amirali H. Further Mathematics tutor
2033 Views

Using differentiation, show that f(x) = 2x^3 - 12x^2 + 25x - 11 is an increasing function.

First compute the derivative of f(x) using the power rule on each term. f(x) = 2x^3 - 12x^2 + 25x - 11 so f'(x) = 6x^2 - 24x + 25. Now complete the square for the derivative. f'(x) = 6 * ((x-2)^2 - 4) + 2...

Answered by Michael T. Further Mathematics tutor
2892 Views

f(x) = 3x^3 – x^2 – 20x – 12 (a) Use the factor theorem to show that (3x + 2) is a factor of f(x). [2 marks] (b) Factorise f(x) fully. [3 marks]

(a) Factor theorem hence, use x = -2/3. Sub in : 3(-2/3)3 - (-2/3)2 -20 (-2/3) -12 = 0 (b) (3x+2)(ax2 + bx+c) = 3x3 – x2 – 20x – 12 3ax3

Answered by Daniel W. Further Mathematics tutor
3397 Views

Find the coordinates of the minimum point of the function y=(x-5)(2x-2)

At the minimum point the gradient is zero so dy/dx=0. To find dy/dx, first expand out the brackets so y=2x^2 - 12x + 10. Using differentiation dy/dx=4x - 12. At the minimum 4x-12=0 so 4x=12 therefore x=3....

Answered by Phoebe C. Further Mathematics tutor
1774 Views

The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel.

Two lines are parallel if they have the same gradient. This can be found by looking at the coefficient of x. When the equation is written in the form y=ax+b, with b a constant, the gradient of the line wo...

Answered by Joe S. Further Mathematics tutor
1548 Views

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