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To solve this equation we need to expand the right hand side to get: x^2 = 4(x^2-6x+9), then we multiply whats in the bracket by 4 to get: x^2 = 4x^2 - 24x +36. We can subtract x^2 from both sides to give...
5x-2=3x+11
Move the (-2) to the right handside. As it crosses over the (-) becomes a (+)
5x=3x + (11+2)
Move the (+3x) to the left handside. As it crosses over the (-) becomes a (+)
We'll first compute these intersections by setting x=0 and y=0 consecutively. This gives y=a-1 and a/(x-1)^2-1=0. Hence we find (x-1)^2=a, so x=1+-sqrt(a). As we have a>1 and we want the intersection w...
We know that non-real roots appear in complex conjugate pairs. Hence when we know one root, we know both of them. Then, as we can factorise a quadratic in it's linear factors, we know our quadratic is a c...
The answer is Ln8/9, by first converting (1-x)/(5x-6-x^2) into partial fractions you get 1/(2-x) + 2/(x-3), the next step is a simple integration by inspection followed by log manipulations to get the fin...
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