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Solve the simultaneous equations: (a) y - 2x = 6; (b) y+2x = 0.

  • rearrange equation (a) to be: y = 6 + 2x. Substitute this into equation (b) to get: (6 + 2x) + 2x = 0

  • rearrange this to get: 6 + 4x = 0. Simplify to get x = -(6/4). Get the val...

Answered by Faizan M. Maths tutor
9589 Views

May you please help me solve these algebra problem set ?

I would go through one of the problem on the interactive board with the student and ask them to try next question alone.

Answered by Tara M. Maths tutor
2611 Views

Find the minimum value of the function, f(x) = x*exp(x)

The minimum value lies where the tangent to the curve has a gradient of zero and the curve approaching from both directions increases in value. This is done by finding the first and second derivatives of ...

Answered by Robin T. Maths tutor
2927 Views

1a) Simplify 2a^3 x a^5 1b) (4x^2)^3 1c) 2(3y+1) - 3(y-4)

1a) To simplify this into one expression you first multiply together the co-efficients, therefore 2a x a = 2a. Then for indices when they are multiplied together you add them, so the simplification would ...

Answered by Freddie I. Maths tutor
3319 Views

Given the function f(x) = 2x^2 + 3.When f(x) = 53 find both values of x

Sub in f(x)=53 into equation. So you have 53=2x^2+3, deduct 3 from both sides to get 50=2x^2 and then divide each side by 2 to get 25=x^2 and finally square root both sides to get x=5 or x=-5.

Answered by Jack W. Maths tutor
5325 Views

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