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So here we want to eliminate one variable so we are only working with either x or y by themself, so to do this we can rearrange the first equation of x+y=1 to x= 1-y. This new equation can therefore be su...
Remember the rule BIDMAS (Brackets, Indicies, Division, Multiplication, Addition, Subtraction)
Inside the brackets we have: 12 - 32 and again need to remember BIDMAS. The next item to co...
First notice that two numbers have 0 before the decimal point. Conclude to ignore the rest. Then compare the remaining two by adding a zero to the end of 0.8 thus making 0.80. Now compare 0.80 with 0.88 a...
Rearrange AB into y = mx + c format: 1) 3y = -3 - 5x 2) y = - 5/3 x - 1
Compare equation with y = mx + c
Conclude m = - 5/3
You can also deduce the y-intercept of AB is -1.
Expand the brackets: 4m - 8 = 5tm + 3t
Collect all m variables to one side: 4m - 5tm = 3t + 8
Take a factor of m out: m(4 - 5t) = 3t + 8
Divide both sides by (4 - 5t): m = (3t + 8) / ...
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