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Begin by differentiating the terms in the brackets, which gives just 6x. Bring 6x forward, out of the brackets, together with the index on the brackets - 1/3. This gives 42x/3 or 14x in front of the brack...

(2x-5)/(x+5)

Here we can either use the substitution method or the elimination method. The elimination method here would be hard to carry out due to there being no term which we can make equal in terms of only one of ...

Differentiation is very helpful in the real world, in many different fields. In terms of business and economics, being able to derive maximum and minimum values of certain functions can prove extremely us...

Notice that (sin(x))'= cos(x) and (x^2)' = 2x

We use the product rule to differentiate, by noticing the expression is a product. 

so (fxgx)' = f'xgx + fx*g'x

substituting in ...