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Jo wants to work out the solutions of x^2 + 3x – 5 = 0 She says, ‘‘The solutions cannot be worked out because x^2 + 3x – 5 does not factorise to (x + a)(x + b) where a and b are integers.’’ Is Jo correct?

She is not correct. We can solve a quadratic equation in other ways. The easiest way is to use the formula for quadratic equations.x = (-b +/- sq. root (b^2 - 4ac) / 2ax = -3 +/- sq. root 3^2 - 4x -5 / 2 ...

Answered by Kirsty A. • Maths tutor

3238 Views

The range of a set of numbers is 15 1/4. The smallest number is –2 7/8. Work out the largest number.

First we need to understand what the range is. It is the difference between the smallest and largest numbers in a sample or list or numbers. If we add the range on to the smallest number we get the larges...

Answered by Kirsty A. • Maths tutor

9496 Views

Calculate the value of x

Angle AOB = 2x + 28. An angle at the circumference is half that at the centre, so angle ACB = x + 14. Opposite angles of a cyclic quadrilateral sum 180° , so ACB + ADB = 180. ADB is given as 3x - 70. This...

Answered by Eleanor L. • Maths tutor

4672 Views

Solve the following simultaneous equations: 3y=7+5x (1) 9x=-7y-4 (2)

Rearrange (2): x=(-7y-4)/9Substitute the value of x from (2) into (1): 3y=7+5*(-7y-4)/9 Simplify and rearrange for y: y+(35y/27)=(7/3) -(20/27)Resolve for y: y=43/62Substitute y into (1): (3*63)/62=7+5xRe...

Answered by Nabil F. • Maths tutor

2511 Views

Solve x(x-1)-12=0

Expand the brackets to find x²-x-12=0Factorise the equation to find (x-4)(x+3)=0Check it expands to equal x²-x-12=0Find the value of x as:x+4=0 therefore X=4x-3=0 therefore X=-3

Answered by Sarah W. • Maths tutor

2276 Views