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Maths
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X^2 -25 Find the solution to this equation.

candidate should recognise the equation is a difference between two squares.
the next step is to factorise: square root of 25 is 5
(x-5)(x+5) = x^2-25
x= -5 x= 5

JD
Answered by Jakub D. Maths tutor
3098 Views

If x^2 + 2y = -14 and y = 4x + 1 , by using the quadratic formula, find the possible values for x.

First the equation for y must be substituted into the first equation to give a quadratic equation in x. Rearrange this equation so that the left-hand side equals 0. Using the quadratic formula the possibl...

RW
Answered by Rachael W. Maths tutor
2647 Views

3A + 4B =32 6A-2B=14 work out the values of A and B

First we need to get either an equal number of As, an opposite number of As. An equal number of Bs or an opposite number of Bs. 6A-2B= 14 (Multiply by 2) 12A-4B =28 and 3A +4B =32 add together15A=60 (divi...

OR
Answered by Oliver R. Maths tutor
2958 Views

a right-angled triangle has base 2x + 1, height h and hypotenuse 3x. show that h^2 = 5x^2 - 4x - 1

initially, explain Pythagorean's Theory --> a^2 + b^2 = c^2.explain c is the hypotenuse, a and b can be either base or height.using a as base and b as height, a = 2x+1. b = h. c = 3xsubstitute into for...

MA
Answered by Mohammad A. Maths tutor
3208 Views

Solve the following system of equations simultaneously to find the values of x, y and z. 2x+3y+4z=3, -x-y+z=1, 2x+y-z=0

First scale one of the equations so that upon addition or subtraction from another of the equations we cancel one of the 3 variables, next do this again replacing one of the equations used with the unused...

SA
Answered by Shaun A. Maths tutor
2754 Views

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