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Find the solutions to the simultaneous equations

y - 2x = 3 x2 + y2 = 18Step 1- re-arrange the first formula to find y: y = 3 + 2x Step 2- Substitution: x2 + ( 3 + 2x )2 = 18 Step 3- Expand the brackets: ( 3 +...

Answered by Rebecca H. Maths tutor
2279 Views

Find the roots of the following curve: y = 6x^2 - 4x.

The two terms in the quadratic equation share the factors 2 and x, so these can be brought outside the bracket as shown: y = 2x(3x-2). In order to solve ...

Answered by Sam K. Maths tutor
2197 Views

Complete the square of X^2 + 4X - 12

X^2 + 4X - 12X^2 + yX + z(x + a)^2 + ba = y/2a = 4/2 = 2b = z - a^2b = -12 -2^2 = -16Therefore: x^2 + 4x - 12 = (x+2)^2 - 16

Answered by Anastasia R. Maths tutor
2140 Views

Work out the value of (16/81)^3/4

Treat each component separately and break it down...Note that when a number has a power that is a fraction, the numerator acts as a power and the denominator acts as a root(16)^1/4 = 2. Okay, brilliant!So...

Answered by Maisie T. Maths tutor
5307 Views

Make s the subject of: v^2= u^2+2as

The aim of this question is to algebraically manipulate the equation to end up with an equation with s on its own, on one side, making it the subject of the equation.We will start by looking at the terms ...

Answered by Divya D. Maths tutor
49090 Views

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