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You can find the stationary points by differentiating the equation and then solving it for zero. What this means, is that you can take the power of the Xs in the equation, and differentiate by bringing th...

To solve these equations, we have to rearrange the second equation to make x ‘the subject’ and then we can substitute it into the first one. First, subtract 2y from both sides so x=1-2yNext substitute thi...

3xy+6x^2There is a common factor of x in both terms so we can factor x out of the expressionx(3y+6x)There is also a common factor of 3 in both terms so we can factor that out also3x(y+2x)

Make the like terms equate by multiplying (1)*2 and (2)*3, ((1)*2) 24x+7y=64, ((2)*3) 24x+9y=72, Take one away from the other to remove the x term and solve for y, (24x+9y=72) - (24x+7y=64), 2y=8 y=4, Su...

2y + 3x = 19y + 7x = 26
so2y + 3x = 192y + 14x = 52
minus the top from the bottom11x = 33x= 3
put x into the initial questiony + 7(3) = 26y = 26-21y=5