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-Firstly we should check if the equation has the variables separated (x on one side and y on the other side of the equal sign), which they apear to are, therefore we can proceed to the next step. As it is...

6x³ + 8x² -15x = 0x(6x² + 8x - 15) = 0x=06x² + 8x - 15 = 0Quadratic formula ( can demonstrate in interview)x = 0 or x = 1.049 or x = -2.38

First notice that f(x) = u/v. So f'(x) =[ v(u') - u(v')]/v² (the Quotient rule). After working it out, we find f'(x) = 6x/(x² + 5)² (the steps can be shown on the whiteboa...

Take u = 1+3x² , this gives that y = u^1/3 . By the chain rule we have that dy/dx = dy/du * du/dx. By differentiating y = u^1/3 with respect to u giv...

first of all we have to recognise the general form of the equation, similar to the equation of a line but we just have to add one more term due to the fact that it is a second degree equation: y=ax^2<...