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For this you’ll want to use the integration by parts method. In this the form u use is:integral of udv = uv - integral of vduTherefore we can rewrite the integral as ln(x)*1 labelling 1 as dv and ln(x) as...

using pythagorus ( c^2 = b^2 + a^2) and plugging in 3 and 4 as a and b we get c^2 = 3^2 + 4^2 = 9 + 16 = 25. Taking the positive square root as sides can't be negative we get c = 5

First thing to note: this is a sketch question, and we're asked to sketch a quadratic (because there's an x² term). So we need to factorise (put the brackets i...

The first step is to remember that the equation of every straight line can be expressed as:y=mx+cSo we need to find the values of m and c. We have a rule that tells us the gradient of perpendicular lines-...

b = (Fc-t^2)/4